Refraction of Light PART I
This laboratory was designed to investigate the behaviour of light as it travels through a less dense into a denser medium.
Materials
- Ray Box with comb
- Semicircular plastic block
Procedure
- Placed the semicircular plastic block on the centre of a blank sheet of paper. Traced its outline and indicated the centre of the flat side.
- Directed a single ray of light from the raybox to the centre of the flat side at an angle of incidence of about 0˚. Marked the location of the incident and emergent ray.
- Directed the raybox to the centre of the flat side at 5 different incident angles. Marked the location of all the incident and emergent rays.
- Removed the block and complete sets of rays were drawn.
Analysis
Angle of Incidence (° from nearest normal) | Angle of Refraction (° from nearest normal) | Sine of Angle of Incidence (° from nearest normal) | Sine of Angle of Refraction (° from nearest normal) |
15 | 10 | 0.173648 | 0.258819 |
30 | 20 | 0.34202 | 0.5 |
45 | 29 | 0.48481 | 0.707107 |
60 | 35 | 0.573576 | 0.866025 |
75 | 41 | 0.656059 | 0.965926 |
The sine of the angle of incidence is equal to the sine of the angle of refraction multiplied by 1.4797
Conclusion
From the above “SIN <i vs. SIN <r” graph, a clear relationship is established:
Sine of Angle of Incidence α Sin Angle of Refraction
SIN <i α SIN <r
SIN <i = SIN <r × K
SIN <i = SIN <r × 1.4797
SIN <i × 1 = SIN <r × 1.4797
This relationship is also known as Snell’s Law.
When light passed from air into a denser medium, the ray of refraction bent towards the normal. Also, the angles of incidence and the angles of refraction were not directly proportional in contrary to the sin of the incident and refraction angles. Moreover, the observations and graph shows that the ratio sin i / sin R is a constant for any given medium and that although the incident and refracted ray appeared on opposite sides of the normal, but they all lie in the same plane.
Refraction of Light PART II
Introduction
This laboratory was designed to investigate the behaviour of light as it travels through a denser into a less dense medium.
Materials
- Ray Box with comb
- Semicircular plastic block
Procedure
- Placed the semicircular plastic block on the centre of a blank sheet of paper. Traced its outline and indicated the centre of the flat side.
- Directed a single ray of light from the raybox to the centre of the curved side at an angle of incidence of about 0˚. Marked the location of the incident and emergent ray.
- Directed the raybox to the centre of the curved side at 5 different incident angles. Marked the location of all the incident and emergent rays.
- Removed the block and complete sets of rays were drawn.
Analysis
Angle of Incidence (° from nearest normal) | Angle of Refraction (° from nearest normal) | Sine of Angle of Incidence (° from nearest normal) | Sine of Angle of Refraction (° from nearest normal) |
15 | 24 | 0.406737 | 0.258819 |
30 | 50 | 0.766044 | 0.5 |
35 | 65 | 0.906308 | 0.573576 |
40 | 80 | 0.984808 | 0.642788 |
45 | Total Internal Reflection | N/A | N/A |
60 | N/A | N/A | |
75 | N/A | N/A |
The angles corresponding with 45°, 60°, and 75° weren’t used because they were reflected rays and not refracted.
From the above graph, it is clear that another relationship, similar to the one found in “Refraction of Light I” exists.
Sine of Angle of Incidence α Sin Angle of Refraction
SIN <i α SIN <r
SIN <i = SIN <r × K
SIN <i = SIN <r × 0.6452
SIN <i × 1.4797 = SIN <r × 1
In this case, the indexes of refraction have been reversed.
Snell’s law states that when traveling from a denser to a less dense index, the angle of incidence will be less than the angle of refraction. Since plastic is denser than air, the incident ray will bend away from the normal when it travels through the air. However, at a certain angle of incidence, the emergent ray is a reflected ray. This can be seen by using Snell’s law. If you plug in all of the values, you’ll get that SIN > 1, and hence, it’s impossible. However, this never happens, so instead, the ray is reflected.
The conditions for total internal reflection to occur are:
i. Light must be travelling in the more refractive medium.
ii. The angle of incidence in the more refractive medium must be larger than the critical angle.
The critical angle refers to an angle of incidence that produces a corresponding emerging ray that has an angle of refraction of 90°. It is the largest possible angle of incidence that doesn’t result in total internal reflection. In this activity, it was estimated to be 43°.
Conclusion
By doing this experiment it can be proved that there are special cases when light travels to different mediums (high to low density). When the angle of incidence is greater than the critical angle, light doesn’t follow Snell’s Law. Instead of refracting, the ray of light reflects. Apart from this difference in refraction, Snell’s Laws is followed throughout.
Thanks