Calculate the Shannon’s Diversity Index along with the Simpson’s Diversity Index for Species A, Species B and Species C respectively then state which species is more diverse and explain why it is more diverse.

## CALCULATIONS

SPECIES A

A) Shannon – Weiner Index

H1=[NlnN-∑(ni ln ni)]/ N

where N is the total number of species and ni is the number of individuals in species.

For species A

N=11+12+13+15+16+12+15+17+16+15=142

For species A

B) SIMPSON’ DIVERSITY

Species A

N is the total number of species in the sample and ni is the total number of individual species .

From the above calculation N is equal to 142 and ni is shown in the table below-

SPECIES B

a) Shannon – Weiner Index

H1=NlnN-∑(ni ln ni)/ N

where N is the total number of species and ni is the number of individuals in species.

For Species b N=21+21+22+18+18+25+27+29+20+26=227

SPECIES B

SIMPSON’ DIVERSITY

b) N is the total number of species in the sample and ni is the total number of individual species.

From the above calculation N is equal to 227 and ni is shown in the table below-

SPECIES C

a) Shannon – Weiner Index

H1=NlnN-∑(ni ln ni)/ N

where N is the total number of species and ni is the number of individuals in species.

For species c N =31+37+40+44+43+42+40+42+30+38=387

SPECIES C

b) SIMPSON’ DIVERSITY

N is the total number of species in the sample and ni is the total number of individual species.

I have found N to be 387 from the above the calculation.

The compliment to SIMPSONS D, the value is  –

1-0.092=0.908

Species A is more diverse .

The value of Simpson’s D ranges from 0 to 1, with 0 representing infinite diversity and 1 representing no diversity, so the larger the value of D , the lower the diversity. For this reason, Simpson’s index is usually expressed as its inverse (1/D) or its compliment (1-D).

Using the inverse, the value of this index starts with 1 as the lowest possible figure. The higher the value of this inverse index the greater the diversity.

The higher value of the inverse index is species A which is 10.4932

Therefore the  more diverse species is species A.

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